Isomorphic pixelated robot at home

#isomorphic #pixelated #pixelart #8bit #videogame #robot #ai #aivideo #aiart #aiartcommunity #wan #wanai

Isomorphic Labs, el negocio de drogas de IA de Google, recauda cuartos de Thrive #dinero #drogas #Google #Isomorphic #Labs #negocio #recauda #Thrive #ButterWord #Spanish_News Comenta tu opinión 👇
https://butterword.com/isomorphic-labs-el-negocio-de-drogas-de-ia-de-google-recauda-cuartos-de-thrive/?feed_id=14826&_unique_id=67eb1eeb28e59

🌘 Alphabet的人工智慧單位Isomorphic與愛力莉和諾華達成價值高達30億美元的藥物發現協議-Endpoints新聞
➤ Alphabet的Isomorphic與Eli Lilly和Novartis簽訂藥物發現協議
✤ https://endpts.com/alphabets-ai-unit-isomorphic-inks-drug-discovery-deals-with-eli-lilly-novartis-for-up-to-3b/
Alphabet旗下的人工智慧初創公司Isomorphic與Eli Lilly和Novartis簽訂了首批藥物合作協議，項目價值高達30億美元。Isomorphic將應用Google DeepMind的生物學研究成果，尤其是Alphafold的蛋白結構預測模型，進行藥物發現。此為Isomorphic取得的重要里程碑，將推動人工智慧在生物科技領域的發展。
+ 這將是一個重要的合作，有助於推動人工智慧在藥物研發領域的應用。
+ 期待Isomo
#藥物發現 #Alphabet #Isomorphic #Eli Lilly #Novartis

New Dolores Catherino track is out!

https://youtu.be/74O9FmnFpjw

#microtonal #polychromatic #isomorphic

Dolores Catherino has released a new track

https://youtu.be/duwEV4PrrqE

#music #microtonal 56edo #isomorphic

Are there any #isomorphic 2 player tabletop/simple #games?

ie. You’re playing Game A and I’m playing Game B, but some method of noting down our choices means we’re playing valid moves against each other?

(I’m sure some #maths / #math folks might find this q question interesting!)

Marko JS
@MarkoDevTeam
A declarative, HTML-based language that makes building web apps fun

#nodejs #javascript #isomorphic #frontend #dom #serversiderendering #vdom #clientsiderendering #uicomponents #webdev

markojs.com/

There are several #Mastodon clients for #JavaScript out there, but at the moment only https://github.com/neet/masto.js looks maintained and reasonable implemented. Its using #TypeScript is #Isomorphic . It has reasonable good documentation with examples, API docs, CI setup. Some test coverage but could be improved. #mastojs #nodejs

#isomorphic keyboard is a musical input device consisting of a two-dimensional grid of note-controlling elements

When are Are (a ->b)-> c and a-> (b*c) #isomorphic ?
Diagonal #haskell

- By #Cayley's theorem, every group is #isomorphic to some #permutation group.

The way in which the elements of a permutation group permute the elements of the set is called its group action

#Hilbert space and its continuous dual space. If the underlying field is the real numbers, the two are isometrically #isomorphic; if the underlying field is the complex numbers, the two are isometrically anti-isomorphic.

Let f be a scaler , which by the way, can be treated as a linear map, once we pick basis of a #vector v - n, v is tulle of n scalers from f and n-d space is #isomorphic to f^n

#tensor product of V w its dual space S is #isomorphic to space of linear maps M : V -> V: a #dyadic tensor vf is M sending any w in V to f(w)v. When V is Euclidean n-space, inner product can identify S w V i->dyadic tensor tensor product of two vectors in Euclidean space.

#tensor product of V w its dual space S is #isomorphic to space of linear maps M : V -> V: a #dyadic tensor vf is M sending any w in V to f(w)v. When V is Euclidean n-space, inner product can identify S w V i->dyadic tensor tensor product of two vectors in Euclidean space.

All metric spaces have #Hausdorff completions c, let L1 be C of normed vector space c_c. C_c is #isomorphic to space of #Lebesgue integrable functions #modulo subspace of functions w integral 0. Riemann
∫ is a uniformly continuous functional wrt norm on Cc, dense in L1. ∫

All metric spaces have #Hausdorff completions c, let L1 be C of normed vector space c_c. C_c is #isomorphic to space of #Lebesgue integrable functions #modulo subspace of functions w integral 0. Riemann
∫ is a uniformly continuous functional wrt norm on Cc, dense in L1. ∫

any 2 bases for a free module over an IBN ring have the same cardinality. Assuming the ultrafilter lemma (a strictly weaker form of #axiomofchoice), this result is actually equivalent to definition : positive integers m, n can't exist w ring R S.t. R^m and R^n are #isomorphic

any 2 bases for a free module over an IBN ring have the same cardinality. Assuming the ultrafilter lemma (a strictly weaker form of #axiomofchoice), this result is actually equivalent to definition : positive integers m, n can't exist w ring R S.t. R^m and R^n are #isomorphic